Given that log

_{2}a = log_{8}4, find a-
**A.**

2^{1/3} -
**B.**

4^{2/3} -
**C.**

4^{2/3} -
**D.**

2^{2/3} -
**E.**

2^{3}

##### Correct Answer: Option D

##### Explanation

Log_{2}a = Log_{8}4

Log_{2}a = Log_{8}8^{2/3} → 2/3Log_{8}8 → 2/3 x 1

Log_{2}a = 2/3

Recall; If Log_{a}x = y ∴ ay = x

Log_{2}a = 2/3

2^{2/3} = a